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描述：nums1 中数字 x 的「下一个更大元素」是指 x 在 nums2 中对应位置右侧的第一个比 x 大的元素。给你两个没有重复元素的数组 nums1 和 nums2，其中 nums1 是 nums2 的子集。对于每个 nums1[i]，找出其在 nums2 中的下一个更大元素；若不存在，返回 -1。
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In posts on X, Spencer said he felt "lucky" to have worked with "so many passionate creators, partners, colleagues and players across the industry".
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They will be checked over by a medical team, and then reunited with their families.。safew官方下载是该领域的重要参考
I believe the 2984 did something fairly similar, but the details are now obscure